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## How To Solve A Rubik's Cube 2X2

How To Solve A Rubik's Cube 2X2. Now, depending on the new arrangement of the colors of this cube. Solve the 2×2 rubik's cube.

Now, depending on the new arrangement of the colors of this cube. Okay, let's learn to solve our 2×2. For simplicity and familiarity we will make yellow the top which will make the bottom white.

### Solve The 2X2 Rubik's Cube.

First we will solve the first layer, the bottom layer. Okay, let's learn to solve our 2×2. How to solve the 2×2.

### It Is Important To Know That The 2X2 Rubik’s Cube Doesn’t Have The Center Pieces To Guide Us, Which Is A Challenge To Overcome.

Now, depending on the new arrangement of the colors of this cube. If you can already solve a 3×3, you can skip this step because it’s just like inserting first layer corners. The pocket cube is an easier puzzle than the rubik's cube.

### To Start Solving A 2X2 Rubik’s Cube, Lets Start With Solving The First Layer.

Layer by layer beginner method to solve 2×2 cube. If you have not learned the algorithms from a 3×3 tutorial, you must learn them now or you will not be able to solve this rubik's cube, because it's so hard. For this step of our 2×2 rubik’s cube solver, our goal is to solve the white side so the whites are all on the same side and the colors attached to the white sides match each other.

### 2×2 Rubik’s Cube Is Just A Mini Version Of The 3×3 Rubik’s Cube.

At the end of the stage, you should have the upper part solved. You can solve rubik’s cube 2×2 simply by. Erno rubik, the inventor of 3×3 rubik’s cube, invented the mini cube.

### To Solve The 2×2 Rubik’s Cube We Are Going To Use The Same Layer By Layer Method We Use For The 3×3… Minus Middle Layer.

This is the 2×2 version of erno rubik’s original rubik’s cube. R' u r u' r' if the two matching edges are opposite one another, hold the cube so that they are on the left and right faces (shown in the right picture) and perform the following algorithm to swap the one in the back and in the front: Anyone looking at this cube may assume it to be very easy to solve, until knowing that it has around 3.5 million possible permutations.